Oracle数据库⽣成2022年节假⽇表SQL -- day_typ 0：⼯作⽇ 1：休息⽇ 2：节假⽇
insert into wkday
(wk_day, day_typ)
select wk_day,
case
when wk_day in ('20220101',
'20220102',
'20220103',
'20220131',
'20220201',
'20220202',
'20220203',
歇后语大全及答案搞笑'20220204',
'20220205',
'20220206',
'20220403',
干部作风整顿心得体会'20220404',
'20220405',
好听的女孩英文名字'20220430',
'20220501',
'20220502',
'20220503',
'20220504',
'20220603',
'20220604',
'20220605',
'20220910',
'20220911',
'20220912',
'20221001',
'20221002',
'20221003',
'20221004',
'20221005',
'20221006',
'20221007') then
'2'
when wk_day in ('20220129',
'20220130',
'20220402',
'20220424',
'20220507',
'20221008',
'20221009') then
汽车省油'0'
else
day_typ犯罪电影
end day_typ
from (select wk_day,
case
when trim(to_char(to_date(wk_day, 'YYYYMMDD'), 'day')) in
('星期六', '星期⽇') then
'1'
else
'0'
带有风的诗句end day_typ
from (select to_char(to_date('20220101', 'yyyyMMdd') + rownum - 1, 'yyyymmdd') as wk_day
from dual
connect by rownum <=
trunc(to_date('20221231', 'yyyyMMdd') -
to_date('20220101', 'yyyyMMdd')) + 1))
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