oracle数据库密码复杂度查询,Oracle11gR2创建
PASSWORD_VERIFY。。。
Oracle 11gR2创建PASSWORD_VERIFY_FUNCTION对应密码复杂度验证函数步骤
运⾏测试环境：数据库服务器Oracle Linux 5.8 + Oracle 11g R2数据库粽子情短句
相关⼯具：PL/SQL软件(连接Linux下的Oracle数据库),SecureCRT软件(远程连接Linux服务器)
详细步骤：
1、连接上Linux数据库服务器，切换到Oracle数据库⽤户桌⾯，打开终端，进⼊到环境变量$ORACLE_HOME⽬录
Last login: Fri Dec 11 13:26:18 2015 from 192.168.1.100
[root@Linux主机名 ~]# su - oracle
[oracle@Linux主机名 dbhome_1]$ cd $ORACLE_HOME/rdbms/admin
[oracle@Linux主机名 admin]$
2、查看Oracle11g数据库提供的默认密码复杂度函数脚本(Oracle安装⽬录下的/rdbms/admin/utlpwdmg.sql⽂件) [oracle@Linux主机名 admin]$ cat $ORACLE_HOME/rdbms/admin/utlpwdmg.sql
脚本详细内容详见⽂章末尾
3、登录Oracle数据库并执⾏Oracle11g数据库提供的默认密码复杂度函数脚本
[oracle@Linux主机名 admin]$ sqlplus /nolog
SQL*Plus: Release 11.2.0.1.0 Production on Fri Dec 11 13:33:58 2015
Copyright (c) 1982, 2009, Oracle. All rights reserved.
SQL> conn /as sysdba
Connected.
做汤圆SQL> @?/rdbms/admin/utlpwdmg.sql
Function created.
Profile altered.
Function created.
SQL>
4、在PL/SQL中创建⽤户的资源⽂件，执⾏下⾯语句
CREATE PROFILE 资源⽂件名 LIMIT
SESSIONS_PER_USER UNLIMITED
CPU_PER_SESSION UNLIMITED
CPU_PER_CALL UNLIMITED
CONNECT_TIME UNLIMITED
IDLE_TIME 600 --10⼩时连续不活动的话系统⾃动断开连接
LOGICAL_READS_PER_SESSION UNLIMITED
LOGICAL_READS_PER_CALL UNLIMITED
COMPOSITE_LIMIT UNLIMITED
PRIVATE_SGA UNLIMITED
FAILED_LOGIN_ATTEMPTS 10 --指定锁定⽤户的登录失败次数为10次，超过10次则系统被⾃动锁定
PASSWORD_LIFE_TIME 180 --指定⽤户同⼀密码锁允许使⽤的天数为180天
PASSWORD_REUSE_TIME UNLIMITED
PASSWORD_REUSE_MAX UNLIMITED
PASSWORD_LOCK_TIME 1 --指定⽤户被锁定天数为1天
PASSWORD_GRACE_TIME 10 --数据库发出警告到登录失效前的宽限天数
PASSWORD_VERIFY_FUNCTION verify_function_11G
5、测试更新⽤户密码
--创建⽤户并使⽤⾃定义的配置⽂件
create user ⽤户名 identified by 密码 default tablespace 默认表空间名 temporary tablespace 临时表空间名 profile 资源⽂件名; --⽤户授权喜剧片 爆笑电影
grant connect,resource,exp_full_database,imp_full_database to ⽤户名;
--更新⽤户密码为简单的字符串
alter user ⽤户名 identified by 123456;
--更新⽤户密码为复杂的字符串
alter user ⽤户名 identified by Csdn_20151211;
6、结论：发现简单密码⽆法更新，复杂的密码更新成功。
附：$ORACLE_HOME/rdbms/admin/utlpwdmg.sql脚本源⽂件内容
Rem
Rem $Header: utlpwdmg.sql 02-aug-2006.08:18:05 asurpur Exp $
Rem
Rem utlpwdmg.sql
Rem
Rem Copyright (c) 2006, Oracle. All rights reserved.
Rem
Rem NAME
Rem utlpwdmg.sql - script for Default Password Resource Limits
Rem
Rem DESCRIPTION
Rem This is a script for enabling the password management features
Rem by setting the default password resource limits.
Rem
如何获得美国绿卡Rem NOTES
Rem This file contains a function for minimum checking of password
Rem complexity. This is more of a sample function that the customer
Rem can use to develop the function for actual complexity checks that the Rem customer wants to make on the new password.
Rem
Rem MODIFIED (MM/DD/YY)
Rem asurpur 05/30/06 - fix - 5246666 beef up password complexity check Rem nireland 08/31/00 - Improve check for username=password. #1390553 Rem nireland 06/28/00 - Fix null old password test. #1341892
Rem asurpur 04/17/97 - Fix for bug479763
Rem asurpur 12/12/96 - Changing the name of password_verify_function Rem asurpur 05/30/96 - New script for default password management
Rem asurpur 05/30/96 - Created
Rem
-- This script sets the default password resource parameters
-- This script needs to be run to enable the password features.
-- However the default resource parameters can be changed based
-- on the need.
-- A default password complexity function is also provided.
-- This function makes the minimum complexity checks like
-- the minimum length of the password, password not same as the
-- username, etc. The user may enhance this function according to
-- the need.
-- This function must be created in SYS schema.
-- connect sys/ as sysdba before running the script
CREATE OR REPLACE FUNCTION verify_function_11G
(username varchar2,
password varchar2,
old_password varchar2)
RETURN boolean IS
n boolean;
m integer;
differ integer;
isdigit boolean;
ischar boolean;如何自酿葡萄酒
ispunct boolean;
db_name varchar2(40);
digitarray varchar2(20);
punctarray varchar2(25);
chararray varchar2(52);
i_char varchar2(10);
simple_password varchar2(10);
reverse_user varchar2(32);
BEGIN
digitarray:= '0123456789';
chararray:= 'abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ'; -- Check for the minimum length of the password
IF length(password) < 8 THEN
raise_application_error(-20001, 'Password length less than 8');
END IF;
-- Check if the password is same as the username or username(1-100)
IF NLS_LOWER(password) = NLS_LOWER(username) THEN
raise_application_error(-20002, 'Password same as or similar to user');
END IF;
FOR i IN 1..100 LOOP
i_char := to_char(i);
if NLS_LOWER(username)|| i_char = NLS_LOWER(password) THEN
raise_application_error(-20005, 'Password same as or similar to user name '); END IF;
END LOOP;
-- Check if the password is same as the username reversed
FOR i in REVERSE 1..length(username) LOOP
reverse_user := reverse_user || substr(username, i, 1);
END LOOP;
IF NLS_LOWER(password) = NLS_LOWER(reverse_user) THEN
raise_application_error(-20003, 'Password same as username reversed');
END IF;
-- Check if the password is the same as server name and or servername(1-100)
select name into db_name from sys.v$database;
if NLS_LOWER(db_name) = NLS_LOWER(password) THEN
raise_application_error(-20004, 'Password same as or similar to server name');
END IF;
FOR i IN 1..100 LOOP
i_char := to_char(i);
if NLS_LOWER(db_name)|| i_char = NLS_LOWER(password) THEN
raise_application_error(-20005, 'Password same as or similar to server name ');
END IF;
END LOOP;
-- Check if the password is too simple. A dictionary of words may be
-
- maintained and a check may be made so as not to allow the words
-- that are too simple for the password.
IF NLS_LOWER(password) IN ('welcome1', 'database1', 'account1', 'user1234', 'password1', 'oracle123', 'computer1', 'abcdefg1', 'change_on_install') THEN
微波炉烤鸡raise_application_error(-20006, 'Password too simple');
END IF;
-- Check if the password is the same as oracle (1-100)
simple_password := 'oracle';
FOR i IN 1..100 LOOP
i_char := to_char(i);
if simple_password || i_char = NLS_LOWER(password) THEN
raise_application_error(-20007, 'Password too simple ');
END IF;
END LOOP;
-- Check if the password contains at least one letter, one digit
-- 1. Check for the digit
isdigit:=FALSE;
m := length(password);
FOR i IN 1..10 LOOP
FOR j LOOP
IF substr(password,j,1) = substr(digitarray,i,1) THEN
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